0=2c^2=20c+50

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Solution for 0=2c^2=20c+50 equation: 



0=2c^2=20c+50

We move all terms to the left:

0-(2c^2)=0

We add all the numbers together, and all the variables

-2c^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{-4}=0$

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